Do objects of built-in types have special static initialisation order precedence?

Question

I\'d have expected the following code to yield a segmentation fault (or otherwise UB):

struct T {
   T();
};

T t;
char const* str = \"Test string\";

T::T()         


        

Answer 1

Built-in types aren't initialised at all, in the normal sense. Commonly, their initial contents are memory-mapped directly from a special region of the binary as part of loading it.