Do objects of built-in types have special static initialisation order precedence?

Question

I\'d have expected the following code to yield a segmentation fault (or otherwise UB):

struct T {
   T();
};

T t;
char const* str = \"Test string\";

T::T()         


        

Answer 1

str is initialized by a constant expression and const char * is a POD type (C++03 terms, but C++11 it is analogous, but with different terms and way more allowed cases). Such an initialization is done in static initialization phase, and the static initialization phase has no issue of order. It happens before any dynamic initialization. t is initialized in the dynamic initialization phase.