Why ruby modulo is different from java/other lang ?

Question

i am basically coming from java background and struggling to understand the modulo operation in Ruby.

(5 % 3)     
(-5 % 3)    
(5 % -3)    
(-5 % -3) 
         


        

Answer 1

Because Ruby defines x.modulo(y) to be x-y*(x/y).floor. See ruby-doc.org