Finding the second smallest integer in array

Question

We are required in our assignment to find the second smallest integer in one array recursively. However, for the sake of understanding the subject more, I want to do it iter

Answer 1

public class SecondSmallestNumberInArray 
        {
            public static void main(String[] args) 
            {
                int arr[] = { 99, 76, 47, 85, 929, 52, 48, 36, 66, 81, 9 };
                int smallest = arr[0];
                int secondSmallest = arr[0];

                System.out.println("The given array is:");
                boolean find = false;
                boolean flag = true;

                for (int i = 0; i < arr.length; i++) 
                {
                    System.out.print(arr[i] + "  ");
                }

                System.out.println("");

                while (flag) 
                {
                    for (int i = 0; i < arr.length; i++) 
                    {
                        if (arr[i] < smallest) 
                        {   
                            find = true;
                            secondSmallest = smallest;
                            smallest = arr[i];
                        } else if (arr[i] < secondSmallest) {   
                            find = true;
                            secondSmallest = arr[i];
                        }
                    }
                    if (find) {
                        System.out.println("\nSecond Smallest number is Array : ->  " + secondSmallest);
                        flag = false;
                    } else {
                        smallest = arr[1];
                        secondSmallest = arr[1];
                    }
                }
            }
        }

    **Output is**

    D:\Java>java SecondSmallestNumberInArray

    The given array is:

    99  76  47  85  929  52  48  36  66  81  9

    Second Smallest number is Array : ->  36

    D:\Java>