Does a templated constructor override the implicit copy constructor in C++?

Question

Does a templated constructor (such as the following) override the implicit copy constructor?

template 
struct Foo
{
    T data;

    // ...

          


        

Answer 1

No, that is not a copy constructor. Section 12.8 ([class.copy]) of the Standard requires that:

A non-template constructor for class X is a copy constructor if its first parameter is of type X&, const X&, volatile X& or const volatile X&, and either there are no other parameters or else all other parameters have default arguments.

The compiler will still implicitly generate a defaulted one.

You can make that explicit (requires C++11) by

Foo(const Foo&) = default;