How to compare if two strings contain the same words in T-SQL for SQL Server 2008?

Question

When I compare two strings in SQL Server, there are couple of simple ways with = or LIKE.

I want to redefine equality as:

If

Answer 1

Try this... The StringSorter function breaks strings on a space and then sorts all the words and puts the string back together in sorted word order.

CREATE FUNCTION dbo.StringSorter(@sep char(1), @s varchar(8000))
RETURNS varchar(8000)
AS
BEGIN
    DECLARE @ResultVar varchar(8000);

    WITH sorter_cte AS (
      SELECT CHARINDEX(@sep, @s) as pos, 0 as lastPos
      UNION ALL
      SELECT CHARINDEX(@sep, @s, pos + 1), pos
      FROM sorter_cte
      WHERE pos > 0
    )
    , step2_cte AS (
    SELECT SUBSTRING(@s, lastPos + 1,
             case when pos = 0 then 80000
             else pos - lastPos -1 end) as chunk
    FROM sorter_cte
    )
    SELECT @ResultVar = (select ' ' + chunk 
                                     from step2_cte 
                                     order by chunk 
                                     FOR XML PATH(''));
    RETURN @ResultVar;
END
GO

Here is a test case just trying out the function:

SELECT dbo.StringSorter(' ', 'the quick brown dog jumped over the lazy fox');

which produced these results:

  brown dog fox jumped lazy over quick the the

Then to run it from a select statement using your strings

SELECT case when dbo.StringSorter(' ', 'my word') = 
                     dbo.StringSorter(' ', 'word my') 
               then 'Equal' else 'Not Equal' end as ResultCheck
SELECT case when dbo.StringSorter(' ', 'my word') = 
                     dbo.StringSorter(' ', 'aaamy word') 
               then 'Equal' else 'Not Equal' end as ResultCheck

The first one shows that they are equal, and the second does not.

This should do exactly what you are looking for with a simple function utilizing a recursive CTE to sort your string.

Enjoy!