`java (0 % 2 != 0) == false`

Question

The part I keep getting stuck on is boolean(0 % 2 !=0) == false. I mean if 2 goes into 0, 0 times then the remainder would be 2, and 2 does not equal 0. S

Answer 1

I think you mix up 0%2 and 2%0 (which is impossible). 0%n is always equal to 0.

Ok, let's dissect that…

1) 0 % 2

modulo is the rest of the finite division. For example 10%3 is the rest of 10/3. 10/3 is 3+⅓. So the rest is 1.

0%2 is the rest of 0/2. 0/2=0, there is no rest, thus 0%2=0.

2) 0 % 2 != 0

It means 0%2 is different than 0. We now know it's false.

3) boolean(0 % 2 != 0)

It's simply casting. You cast the result to a Boolean. Instead of just being some false assumption, it gets the Java value false.

4) boolean(0 % 2 != 0) == false

The == means that there is a test here. The test can be simplified (as shown above) as false == false. Is false equal to false? Yes it is. The result is then true.