warning: format ‘%p’ expects argument of type ‘void *’, but argument 3 has type ‘char **’

Question

I\'m trying to print out the value of argv at this point in my code, but when I try to compile it, I get warning: format ‘%p’ expects argument of type ‘vo

Answer 1

In order to print argv and it's address you need to do

int main(int argc, char* argv[])
{
    int i;
    printf("address of argv = %p\n", (void *)argv);
    for (i = 0; i < argc; ++i)
    {
        printf("%s\n", argv[i]);
    }
    return 0;
}