Logical Expressions in C misunderstanding

Question

So, I was writing some code and I was getting an unexpected output in one part of my program which disrupted the entire system.

I managed to extract and simplify th

Answer 1

From the C Standard (6.5.14 Logical OR operator)

3 The || operator shall yield 1 if either of its operands compare unequal to 0; otherwise, it yields 0. The result has type int.

This expression

++i || ++j && k

is equivalent to

++i || ( ++j && k )

and according to the quote from the Standard the expression returns integer value 1 because ++i is not equal to zero. The subexpression ( ++j && k ) is not evaluated.