Is any() evaluated lazily?

Question

I am writing a script in which i have to test numbers against a number of conditions. If any of the conditions are met i want to return True an

Answer 1

JoshiRaez is the actual correct answer.

Here is an example

a = []

any([True, a[0]])

will fail

On the other side, using OR (or AND) will not fail since its not a function:

a = []
True or a[0]