How to sort unsort: array(1).sort transform of array(2) -> array(3).unsort (reversed array(1).sort

Question

How do you sort, operate on, and then unsort the result?

Assume I have a float array p1 = 0.15,0.3, 0.25, 0.12, .... It is sorted to: p2 = sort(p1

Answer 1

To unsort a list in python using built in functions:

Program:

a=[589,273,981,642,702,883,319,128]
print("a",a)
b=[(p[1],p[0]) for p in enumerate(a)]
print("b",b)
c=sorted(b)
print("c",c)
d=[p[1] for p in c]
z=[p[0] for p in c]
print("d",d)
print("z",z)
y=zip(d,z)
print("y",y)
x=list(y)
print("x",x)
w=sorted(x)
print("w",w)
v=[p[1] for p in w]
print("v",v)
# unsort of z in one statement:
u=[r[1] for r in
    sorted(list(zip([q[1] for q in
        sorted([(p[1],p[0]) for p in
            enumerate(a)])],z)))]  

Output:

a [589, 273, 981, 642, 702, 883, 319, 128]
b [(589, 0), (273, 1), (981, 2), (642, 3), (702, 4), (883, 5), (319, 6), (128, 7)]
c [(128, 7), (273, 1), (319, 6), (589, 0), (642, 3), (702, 4), (883, 5), (981, 2)]
d [7, 1, 6, 0, 3, 4, 5, 2]
z [128, 273, 319, 589, 642, 702, 883, 981]
y 
x [(7, 128), (1, 273), (6, 319), (0, 589), (3, 642), (4, 702), (5, 883), (2, 981)]
w [(0, 589), (1, 273), (2, 981), (3, 642), (4, 702), (5, 883), (6, 319), (7, 128)]
v [589, 273, 981, 642, 702, 883, 319, 128]   
u [589, 273, 981, 642, 702, 883, 319, 128]