Divide a list into multiple lists based on a bin size

Question

I have a list containing more than 100,000 values in it.

I need to divide the list into multiple smaller lists based on a specific bin width say 0.1. Can anyone hel

Answer 1

Binning can be done with itertools.groupby:

import itertools as it


iterable = ['-0.234', '-0.04325', '-0.43134', '-0.315', '-0.6322', '-0.245',
            '-0.5325', '-0.6341', '-0.5214', '-0.531', '-0.124', '-0.0252']

a,b,c,d,e,f,g = [list(g) for k, g in it.groupby(sorted(iterable), key=lambda x: x[:4])]
c
# ['-0.234', '-0.245']

Note: this simple key function assumes the values in the iterable are between -0.0 and -10.0. Consider lambda x: "{:.1f}".format(float(x)) for general cases.

See also this post for details on how groupby works.