How does delete deal with pointer constness?

Question

I was reading this question Deleting a const pointer and wanted to know more about delete behavior. Now, as per my understanding:

delete expressio

Answer 1

operator delete accepts a void*. As part of a test program I overloaded operator delete and found that operator delete doesn't accept const pointer.

How did you try this? It certainly does accept const pointers:

#include 

int main() {
    void* const px = 0;
    delete px;
    ::operator delete(px);
}

This code is correct, compiles (albeit with a justified warning) and executes.

EDIT: Reading the original article – you aren't talking about a const pointer but a pointer to const, which is something else. The reason why this has to work is described there. As for why it's working: others have said this.