Why doesn't the compiler detect out-of-bounds in string constant initialization?

Question

I read this question and its answer in a book. But I didn\'t understand the book\'s justification.

Will the following code compile?

Answer 1

Because "fast enough" simply a pointer to a null terminated string. It's too much work for the compiler to figure out if ever assignment to a char* or char [] is going to go beyond the bounds of the array.