Sizeof(char[]) in C

Question

Consider this code:

 char name[]=\"123\";
 char name1[]=\"1234\";

And this result

The size of name (char[]):4
The size of n         


        

Answer 1

Because there is a null character that is attached to the end of string in C.

Like here in your case

name[0] = '1'
name[1] = '2'
name[2] = '3'
name[3] = '\0'

name1[0] = '1'
name1[1] = '2'
name1[2] = '3'
name1[3] = '4'
name1[4] = '\0'