Why does the 'is' operator say these methods aren't the same? [duplicate]

Answer 1

Methods on are bound to instances at runtime. When you run the following code:

print(Person().sayHello is Person().sayHello)

you create two instances and each time you have a different memory address.

>>> Person().sayHello
>
>>> Person().sayHello
>

Note: All we have in Python is runtime; there is no such thing as a separate compile time.