Count instances of each unique integer in a vector in 1 line of code?

Question

Is there a slick way to rewrite this Julia function, perhaps using just 1 line of code, without making it much slower? (I just started using Julia. It\'s great!) K

Answer 1

I know its old but how about

[sum(zd .== i) for i in unique(zd)]

in a short test it performed better than your initial function (time and memory wise).

Caution: result not sorted!