Passing to a Reference Argument by Value

Question

Consider this simple program:

vector foo = {0, 42, 0, 42, 0, 42};
replace(begin(foo), end(foo), foo.front(), 13);

for(const auto& i : foo) co         


        

Answer 1

You can write a simple function that takes in a reference and returns a value. this will "convert" the reference into a value. This does generate a temporary but it is unnamed and will be destroyed at the end of the full expression. Something like

template
T value(const T& ref)
{
    return ref;
}

And then you can use it like

int main()                                                   
{                                                            
    vector foo = {0, 42, 0, 42, 0, 42};
    replace(begin(foo), end(foo), value(foo.front()), 13);

    for(const auto& i : foo) cout << i << '\t';                                      
}

output:

13  42  13  42  13  42

Live Example