parseInt() parses number literals with exponent incorrectly

Question

I have just observed that the parseInt function doesn\'t take care about the decimals in case of integers (numbers containing the e character).

Answer 1

parseInt has the purpose of parsing a string and not a number:

The parseInt() function parses a string argument and returns an integer of the specified radix (the base in mathematical numeral systems).

And parseInt calls the function ToString wherein all the non numerical characters are ignored.

You can use Math.round, which also parses strings, and rounds a number to the nearest integer:

Math.round("12.2e-2") === 0 //true