Strict comparison

Question

In javascript, there are strict comparison operators op1 === op2 and op1 !== op2 that will compare both type and value. Is there a pythonic way of

Answer 1

You can also use the operator module if you want to be super strict. https://docs.python.org/2/library/operator.html

>>> import operator
>>> operator.eq(True, 1)
True
>>> operator.is_(True, 1)
False

Some of the answers in here are wrong. Python for instance, will not differentiate between some types, for the purpose of some comparisons.

For example:

>>> 1 == 1.0
True
>>> operator.eq(1, 1.0)
True
>>> operator.is_(1, 1.0)
False

Is works better than eq (or ==), but it is dependent on a variable being pointers on the same value, which means there's lots of cases you wouldn't like.

If you want to go deep, implementing this in a shorthand manner, something like this: http://code.activestate.com/recipes/384122/ will let you "kind of" build your own operators.