Deny std::vector from deleting its data

Question

I have the following case:

T* get_somthing(){
    std::vector vec; //T is trivally-copyable
    //fill vec
    T* temp = new T[vec.size()];
    memc         


        

Answer 1

I don't know if you will like this very hacky solution, I definitely would not use it in production code, but please consider:

#include 
using namespace std;

#include 

template
T* get_somthing(){
    std::vector vec = {1,2,3}; //T is trivally-copyable

    static std::vector static_vector = std::move(vec);

    return static_vector.data();
}  

int main() {
    int * is = get_somthing();
    std::cout << is[0] << " " << is[1] << " " << is[2];
    return 0;
}

so, as you can see inside the get_somthing I define a static vector, of same type as you need, and use std::move on it, and return it's data(). It achieves what you want, but this is dangerous code, so please use the good old fashioned copy the data again methodology and let's wait till N4359 gets into the mainstream compilers.

Live demo at: http://ideone.com/3XaSME