How to split string into 2 parts after certain position

Question

For example I have some random string:

str = \"26723462345\"

And I want to split it in 2 parts after 6-th char. How to do this correctly?

Answer 1

As a fun answer, how about:

str.split(/(^.{1,6})/)[1..-1]

This works because split returns the capture group matches, in addition to the parts of the string before and after the regular expression.