How to split string into 2 parts after certain position

Question

For example I have some random string:

str = \"26723462345\"

And I want to split it in 2 parts after 6-th char. How to do this correctly?

Answer 1

Here’s on option. Be aware, however, that it will mutate your original string:

part1, part2 = str.slice!(0...6), str

p part1  # => "267234"
p part2  # => "62345"
p str    # => "62345"

Update

In the years since I wrote this answer I’ve come to agree with the commenters complaining that it might be excessively clever. Below are a few other options that don’t mutate the original string.

Caveat: This one will only work with ASCII characters.

str.unpack("a6a*")
# => ["267234", "62345"]

The next one uses the magic variable $', which returns the part of the string after the most recent Regexp match:

part1, part2 = str[/.{6}/], $'
p [part1, part2]
# => ["267234", "62345"]

And this last one uses a lookbehind to split the string in the right place without returning any extra parts:

p str.split(/(?<=^.{6})/)
# => ["267234", "62345"]