Is it possible to numpy.vectorize an instance method?

Question

I\'ve found that the numpy.vectorize allows one to convert \'ordinary\' functions which expect a single number as input to a function which can also convert a list of inputs

Answer 1

Simple solution without modifying the class

You can use np.vectorize directly on the method on the instance:

class Dummy(object):

    def __init__(self, val=1):
        self.val = val

    def f(self, x):
        if x == 0:
            return self.val
        else:
            return 2


vec_f = np.vectorize(Dummy().f) 


def test_3():
    assert list(vec_f([0, 1, 2])) == [1, 2, 2]

test_3()

You can also create a vectorized function vec_f in your __init__:

Adding a vectorized version to the instance

class Dummy(object):

    def __init__(self, val=1):
        self.val = val
        self.vec_f = np.vectorize(self.f) 

    def f(self, x):
        if x == 0:
            return self.val
        else:
            return 2


def test_3():
    assert list(Dummy().vec_f([0, 1, 2])) == [1, 2, 2]

or with a different naming scheme:

class Dummy(object):

    def __init__(self, val=1):
        self.val = val
        self.f = np.vectorize(self.scalar_f) 

    def scalar_f(self, x):
        if x == 0:
            return self.val
        else:
            return 2


def test_3():
    assert list(Dummy().f([0, 1, 2])) == [1, 2, 2]

test_3()

    test_3()