How to change value of arguments in the function

Question

I try it :

#include 
#include 

void foo(int* x)
{
   x = (int *)malloc(sizeof(int));
   *x = 5;
}

int main()
{

   int a;
           


        

Answer 1

Pointer x is already initialized in formal arguments, malloc will create x pointing to another memory location.

void foo(int* x)
{
 /* x = (int *)malloc(sizeof(int)); */
  *x = 5;
}

Please look at Acme's answer for very good diagrammatic representation.