How to post the viewmodel to action method using JQUERY AJAX in MVC

Question

I want to achieve create (INSERT) screen using $.POST or $.AJAX.

Note: code is working fine without AJAX call..it is already there.. now i need to do ajax call and s

Answer 1

You have forgot to add id selecter:

$.ajax(
      {
          url: '@Url.Action("CreateProduct","ProductManagement")',
          dataType: 'json',
          contentType: 'application/json; charset=utf-8',
          type: 'post',
          data:   $('#frm').serialize(),                      // $('#frm');
          success: function () { alert('s'); },
          error: function (e1, e2, e3) { alert(e2); alert(e1 + ' ' + e2 + ' ' + e3); alert('failure event'); }
      }
    );