How to use DataTemplateSelector with ContentControl to display different controls based on the view-model?

Question

I want to create a simple window that would display different controls (SpinEdit or TextEdit) based on the view-model that is selected.

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Answer 1

You do not need a DataTemplateSelector. WPF provides a mechanism that automatically selects a DataTemplate for the ContentTemplate of a ContentControl according to the type of a Content.

As explained in Data​Template.​Data​Type:

When you set this property to the data type without specifying an x:Key, the DataTemplate gets applied automatically to data objects of that type.

So drop the x:Key value and your DataTemplateSelector, set DataType

and bind the ContentControl's Content to a property that returns either a TInputValueVM or a TInputTextVM:

The appropriate DataTemplate will now be selected automatically.