SQL Server 2008 R2: Delete duplicate rows from tables containing in view

Question

--Creating Table dup1

CREATE TABLE dup1
(
    cola VARCHAR(10),
    colb VARCHAR(10)
);

--Insertion of records

INSERT INTO          


        

Answer 1

Are dup1 and dup2 partitionable table? I mean if you can add a column to them that allows to understand wich table to update. e.g. date so that if you insert a date in an interval you update dup1 else dup2. If you don't have a partitioning column you could create one simply adding a column able to identify the table (e.g. a varchar(1) with value '1' or an int having value 1 for dup1 and 2 for dup2) . This column should be a part of the primary key (here I created an ID). The table could look like this:

CREATE TABLE dbo.dup1
    (
    cola   VARCHAR (10),
    colb   VARCHAR (10),
    ID     INT IDENTITY NOT NULL,
    partit NCHAR (10) CONSTRAINT DF_dup1_partit DEFAULT ('1') NOT NULL CONSTRAINT CK_dup1 CHECK ([PARTIT]='1'),
    CONSTRAINT PK_dup1 PRIMARY KEY (ID, partit)
    )

CREATE TABLE dbo.dup2
    (
    cola   VARCHAR (10),
    colb   VARCHAR (10),
    ID     INT IDENTITY NOT NULL,
    partit NCHAR (10) CONSTRAINT DF_dup2_partit DEFAULT ('2') NOT NULL CONSTRAINT CK_dup2 CHECK ([PARTIT]='2'),
    CONSTRAINT PK_dup2 PRIMARY KEY (ID, partit)
    )

So that the view will be:

CREATE VIEW V_Dup as
SELECT * FROM dup1 UNION ALL 
SELECT * FROM dup2
WITH CHECK OPTION

this way you will be able to use the code I posted before