passing functions and its arguments to another function

Question

I have tree types of sub-functions:

• one without any parameters (arguments),
• second with one parameter
• third with multiple parameters (tuple

Answer 1

by goolging 'python determine number of args for passed function' I found How can I find the number of arguments of a Python function?

I'm pretty sure you don't want the **kwars key, value syntax so I use a func_list regular arg and *args

from inspect import signature


def function_results_sum(func_list, *args):

    arg_gen = (e for e in args)

    return sum([func(*(next(arg_gen)
                       for _ in range(len(signature(func).parameters))))
               for func in func_list])

function_results_sum([no_arg, ident, mult], 7,8,9)
84  

the input can be made flatter by parsing *args for Functions and (presumed) arguments (anything not Type Function)

from inspect import signature
import types


def function_results_sum(*args):

    func_gen = (e for e in args if isinstance(e, types.FunctionType))

    arg_gen = (e for e in args if not isinstance(e, types.FunctionType))

    return sum(func(*(next(arg_gen)
                       for _ in range(len(signature(func).parameters))))
               for func in func_gen)

function_results_sum(no_arg, ident, mult, 10,6,90)
555

order of functions and order of args are important, but separately, can be interleaved:

function_results_sum(no_arg, 10, ident, 6, 90, mult)
Out[399]: 555