Getting indices of ascending order of list

Question

I know that this question has been asked a hundred times, but the answer always seems to be \"use numpy\'s argsort\". But either I am misinterpreting what most people are as

Answer 1

The argsoft() is basically converting your list to a sorted list of indices.

l = [4, 2, 1, 3]

First it gets index of each element in the list so new list becomes:

indexed=[0, 1, 2, 3]

Then it sorts the indexed list according to the items in the original list. As 4:0 , 2:1 , 1:2 and 3:3 where : means "corresponds to".

Sorting the original list we get

l=[1, 2, 3, 4]

And placing values of each corresponding index of old list

new=[2,1,3,0]

So basically it sorts the indices of a list according to the original list. This is as far as i understood. Sorry if i am wrong.