Round off dict values to 2 decimals

Question

I\'m having a hard time rounding off values in dicts. What I have is a list of dicts like this:

y = [{\'a\': 80.0, \'b\': 0.0786235, \'c\': 10.0, \'d\': 10.6         


        

Answer 1

Answering the second part of your question

Try replacing line 5 of your code with:

 v = round(v, 2)

This will round the number to two decimal places. Using round, I get

[{'a': 80.0, 'c': 10.0, 'b': 0.08, 'd': 10.67}, {'a': 80.73, 'c': 10.78, 'b': 0.0, 'd': 10.0}, {'a': 80.72, 'c': 10.0, 'b': 0.78, 'd': 10.0}, {'a': 80.78, 'c': 10.0, 'b': 0.0, 'd': 10.98}]

I am using Python 2.7.2. Here's all the code:

from math import ceil 
import json

y = [{'a': 80.0, 'b': 0.0786235, 'c': 10.0, 'd': 10.6742903},
     {'a': 80.73246, 'b': 0.0, 'c': 10.780323, 'd': 10.0},
     {'a': 80.7239, 'b': 0.7823640, 'c': 10.0, 'd': 10.0},
     {'a': 80.7802313217234, 'b': 0.0, 'c': 10.0, 'd': 10.9762304}]

def roundingVals_toTwoDeci(y):
    for d in y:
        for k, v in d.items():
            v = round(v, 2)
            #print v
            d[k] = v
    return

roundingVals_toTwoDeci(y)
s = json.dumps(y)
print s