open() can't find file given path relative to PYTHONPATH

Question

I did export PYTHONPATH=$PYTHONPATH:/home/User/folder/test. Then I ran python when I was in /home/User/ and checked sys.path - it was

Answer 1

Whenever I want to import a script, relative to current and don't use packages, I usually use

sys.path = [os.path.dirname(__file__) + "/../another_dir"] + sys.path