Getting a function name (__func__) from a class T and a pointer to member function void(T::*pmf)()

Question

Is it possible to write some f() template function that takes a type T and a pointer to member function of signature void(T::*pmf)() a

Answer 1

It seems like what you are trying to achieve, is to get the name of the calling function in assert_test(). With gcc you can use backtace to do that. Here is a naive example:

#include 
#include 
#include 

namespace unit_test 
{
struct test {};
}

std::string get_my_caller()
{
    std::string caller("???");
    void *bt[3];                             // backtrace
    char **bts;                              // backtrace symbols
    size_t size = sizeof(bt)/sizeof(*bt);
    int ret = -4;

    /* get backtrace symbols */
    size = backtrace(bt, size);
    bts = backtrace_symbols(bt, size);

    if (size >= 3) {
        caller = bts[2];

        /* demangle function name*/
        char *name;
        size_t pos = caller.find('(') + 1;
        size_t len = caller.find('+') - pos;

        name = abi::__cxa_demangle(caller.substr(pos, len).c_str(), NULL, NULL, &ret);

        if (ret == 0)
            caller = name;

        free(name);
    }

    free(bts);

    return caller;
}

void assert_test(bool expression, const std::string& message)
{
    if (!expression)
        std::cout << "ASSERTION FAILED " << get_my_caller() << ": " <<  message << std::endl;
}


struct my_test_case : public unit_test::test 
{
    void some_test()
    {
        assert_test(false, "test failed.");
    }
};

int main() 
{
    my_test_case tc;
    tc.some_test();

    return 0;
}

Compiled with:

g++ -std=c++11 -rdynamic main.cpp -o main

Output:

ASSERTION FAILED my_test_case::some_test(): test failed.

Note: This is a gcc (linux, ...) solution, which might be difficult to port to other platforms!