Java Arrays: Finding Unique Numbers In A Group of 10 Inputted Numbers

Question

I\'m at a loss here.

I have this homework assignment where I have to enable the user to input 10 numbers, place them in an array, and figure out which inputted numbe

Answer 1

Check the numbers at they are entered, then keep track of which ones are unique by marking the same positions in a second (boolean) array with true if they are unique and false otherwise.

Then, when you print out the unique values, only print the value from each position in numbers[] if that position in uniques[] contains true.

Scanner input = new Scanner(System.in);
int[] numbers = new int[10];
boolean[] uniques = new boolean[10];

for(int i = 0; i < 10; i++) {
    System.out.println("Please enter a value: \n" + "[" + (i + 1) + "]: ");
    numbers[i] = input.nextInt();
    uniques[i] = true;
    for(int j = 0; j < 10; j++) {
        if(numbers[i] == numbers[j] && i != j) {
            uniques[i] = false;
        }
    }
}

System.out.println("\nThe numbers you entered were: \n");
for(int i = 0; i < 10; i++) {
    System.out.println(numbers[i] + ", ");
}
System.out.println("done.\n\n");

System.out.println("\nThe uniqe numbers you entered were: \n");
for(int i = 0; i < 10; i++) {
    if(uniques[i]) {
        System.out.println(numbers[i] + ", ");
    }
}
System.out.println("done.\n\n");