Java - “String index out of range” exception

Question

I wrote this little function just for practice, but an exception (\"String index out of range: 29\") is thrown and I don\'t know why...

(I know this isn\'t the best

Answer 1

Are you translating this code from another language? You are looping through the string until you reach a null character ("\0"), but Java doesn't conventionally use these in strings. In C, this would work, but in your case you should try

i < y.length()

instead of

y.charAt(i) != '\0'

---

Additionally, the

 y.setCharAt(j,'\0')

at the end of your code will not resize the string, if that is what you are expecting. You should instead try

y.setLength(j)