Exmaple:
[empid date bookid]
----------
1 5/6/2004 8
2 5/6/2004 8
1 5/7/2004 8
1 5/8/2004 6
3 5/8/2004
You can use:
SELECT DISTINCT id
FROM table
GROUP BY empid, bookid
HAVING COUNT(*) > 1
But it will give you duplicates. If, for example, you have 1-8,1-8,1-9,1-9 you will get 1,1 as output because empid 1 has duplicate bookid's for two distinct bookid values. You will need to use SELECT DISTINCT
to filter out the duplicate empid.