Why is 49, 50, 51, 52 stored in the array when I declare testArray[] = {'1','2','3','4','5'}? (C programming)

Question

Why is 49, 50, 51, 52 stored in the array when I declare testArray[] = {\'1\',\'2\',\'3\',\'4\',\'5\'}? How should i initialize a string array? Thanks

Answer 1

Because chars are actually stored as their corresponding value in ASCII.

You can declare your string as follows:

char * myString = "String";