How to make permutation in bash with N! input?

Question

I have to make a permutation in bash with \"eval\" and \"seq\" commands. So I have to make first a permutation that could contain the same numbers, then I have to filter it

Answer 1

If someones curious, heres the solution:

input=3
for i in $(eval echo " {1..$input}{1..$input}{1..$input} "); do
    OK=yes
    for pos1 in $(seq 0 $((x,1)) ); do
        for pos2 in $(seq 0 $((x,1)) ); do
            if [ $pos1 != $pos2 ]; then
                if [ ${i:$pos1:1} == ${i:$pos2:1} ]; then
                    OK=no
                fi
            fi
        done
    done
    if [ $OK = yes ]; then
        echo $i
    fi

done