Splitting XML file into multiple at given tags

Question

I want to split a XML file into multiple files. My workstation is very limited to Eclipse Mars with Xalan 2.7.1.

I can also use Python, but never used it before.

Answer 1

Use Python ElementTree.

Create a file e.g. xmlsplitter.py. Add the code below (where file.xml is your xml file and assuming every row has a unique NAME element.).

import xml.etree.ElementTree as ET
context = ET.iterparse('file.xml', events=('end', ))
for event, elem in context:
    if elem.tag == 'row':
        title = elem.find('NAME').text
        filename = format(title + ".xml")
        with open(filename, 'wb') as f:
            f.write("\n")
            f.write(ET.tostring(elem))

Run it with

python xmlsplitter.py

Or if the names are not unique:

import xml.etree.ElementTree as ET
context = ET.iterparse('file.xml', events=('end', ))
index = 0
for event, elem in context:
    if elem.tag == 'row':
        index += 1
        filename = format(str(index) + ".xml")
        with open(filename, 'wb') as f:
            f.write("\n")
            f.write(ET.tostring(elem))