Query group by pair of column result

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一个人的身影
一个人的身影 2021-01-15 11:15

Currently my dataset consist of 4 columns, id, status, user_id, created_date

so after a while the data can be lik

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  •  北荒
    北荒 (楼主)
    2021-01-15 11:30

    You can do it with a left join and then subtract the 2 dates:

    select 
      t.id, 
      t.action_date login_date, tt.action_date logout_date,
      t.user_id,
      (tt.action_date - t.action_date) / 100 session_time
    from (
      select * from session where status = 'LOGIN'  
    ) t left join (
      select * from session where status = 'LOGOUT'    
    ) tt on tt.user_id = t.user_id and 
      tt.action_date = (
        select min(action_date) from session
        where status = 'LOGOUT' and user_id = t.user_id and action_date > t.action_date
      )
    

    See the demo.
    Results:

    | id  | login_date          | user_id | logout_date         | session_time |
    | --- | ------------------- | ------- | ------------------- | ------------ |
    | 1   | 2019-07-16 07:06:55 | Bob     | 2019-07-16 07:29:13 | 22.58        |
    | 3   | 2019-07-16 07:30:31 | Bob     | 2019-07-16 07:49:50 | 19.19        |
    | 5   | 2019-07-16 08:05:55 | Tom     | 2019-07-16 08:15:13 | 9.58         |
    | 7   | 2019-07-16 09:13:55 | John    | 2019-07-16 09:20:13 | 6.58         |
    

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