Comparing list of values against table

Question

I tried to find solution for this problem for some time but without success so any help would be much appreciated. List of IDs needs to be compared against a table and find

Answer 1

there are many built in public collection types. you can leverage one of them like this:

with ids as (select /*+ cardinality(a, 1) */ column_value id
               from table(UTL_NLA_ARRAY_INT(100, 200, 300)) a
            )
select ids.id, case when m.id is null then '**NO MATCH**' else m.value end value
  from ids
         left outer join my_table m
                     on m.id = ids.id;

to see a list of public types on your DB, run :

select owner, type_name, coll_type, elem_type_name, upper_bound, precision, scale from all_coll_types
 where elem_type_name in ('FLOAT', 'INTEGER', 'NUMBER', 'DOUBLE PRECISION')

the hint

/*+ cardinality(a, 1) */

is just used to tell oracle how many elements are in our array (if not specified, the default will be an assumption of 8k elements). just set to a reasonably accurate number.