Using local variables from “child” functions

Question

Consider following code:

function child()
{
    echo $var
}

function parent()
{
    local var=5
    child
}

I\'ve tested it on my machine

Answer 1

bash uses dynamic scoping. The value of var in child is not determined by where child is defined, but by where it is called. If there is no local definition in the body of child, the next place the shell looks is in the body of the function from which child is called, and so forth. The local modifier creates a variable in a function that is local to that call, so it does not affect the value of the variable from any enclosing scopes. It is, though, visible to any enclosed scope.

a () { echo "$var"; }
b () { local var="local value"; a; }

var="global value"
a  # outputs "global value"
b  # outputs "local value"