static_assert of const Variable

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孤街浪徒
孤街浪徒 2021-01-15 06:17

I have this code:

const float foo = 5.0F;

static_assert(foo > 0.0F, \"foo must be greater than 0.\");

But in visual-studio-2010 I get t

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  •  不思量自难忘°
    2021-01-15 06:50

    foo > 0.0F is not a core constant expression:

    1. An expression e is a core constant expression unless the evaluation of e, following the rules of the abstract machine, would evaluate one of the following expressions:

    ...

    (2.7) an lvalue-to-rvalue conversion unless it is applied to

    (2.7.1) a non-volatile glvalue of integral or enumeration type that refers to a complete non-volatile const object with a preceding initialization, initialized with a constant expression, or

    (2.7.2) a non-volatile glvalue that refers to a subobject of a string literal, or

    (2.7.3) a non-volatile glvalue that refers to a non-volatile object defined with constexpr, or that refers to a non-mutable subobject of such an object, or

    (2.7.4) a non-volatile glvalue of literal type that refers to a non-volatile object whose lifetime began within the evaluation of e;

    foo is of floating-point type, for foo > 0.0F an lvalue-to-rvalue conversion on foo is required, which doesn't match the above conditions, then foo > 0.0F is not considered as constant expression:

    A constant expression is either a glvalue core constant expression that refers to an entity that is a permitted result of a constant expression (as defined below), or a prvalue core constant expression whose value satisfies the following constraints

    On the other hand, if declare foo as integral type the code would be fine. LIVE (Usingconstexpr instead of const works too. LIVE)

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