Extracting a list of substrings from MongoDB using a Regular Expression

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感动是毒
感动是毒 2021-01-15 05:53

I need to extract a part of a string that matches a regex and return it.

I have a set of documents such as:

{\"_id\" :12121, \"fileName\" : \"apple.d         


        
3条回答
  •  攒了一身酷
    2021-01-15 06:30

    It will be possible to do this in the upcoming version of MongoDB(as the time of this writing) using the aggregation framework and the $indexOfCP operator. Until then, your best bet here is MapReduce.

    var mapper = function() { 
        emit(this._id, this.fileName.substring(this.fileName.indexOf(".")))
    };
    
    db.coll.mapReduce(mapper, 
                      function(key, value) {}, 
                      { "out": { "inline": 1 }}
    )["results"]
    

    Which yields:

    [
        {
            "_id" : 12121,
            "value" : ".doc"
        },
        {
            "_id" : 12125,
            "value" : ".txt"
        },
        {
            "_id" : 12126,
            "value" : ".pdf"
        },
        {
            "_id" : 12127,
            "value" : ".txt"
        }
    ]
    

    For completness here is the solution using the aggregation framework*

    db.coll.aggregate(
        [
            { "$match": { "name": /\.[0-9a-z]+$/i } },
            { "$group": { 
                "_id": null,
                "extension":  { 
                    "$push": {
                        "$substr": [ 
                            "$fileName", 
                            { "$indexOfCP": [ "$fileName", "." ] }, 
                            -1 
                        ]
                    }
                }
            }}
        ])
    

    which produces:

    { 
        "_id" : null, 
        "extensions" : [ ".doc", ".txt", ".pdf", ".txt" ] 
    }
    

    *current development version of MongoDB (as the time of this writing).

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