Can you translate this debugging macro from C++ to python?

Question

I use this very helpful macro when developing in C++:

#define DD(a) std::cout << #a \" = [ \" << a << \" ]\" << std::endl;std::cout.f         


        

Answer 1

The Rod solution is perfectly usable. It could be even extended to handle many vars. But you can get close to that with much less magic:

def dd(**kwargs):
    print ", ".join(str(k) + "=" + str(v) for k, v in kwargs.iteritems())

a = 1
dd(a=a,b=3)

output:

a=1, b=3