Can you translate this debugging macro from C++ to python?

Question

I use this very helpful macro when developing in C++:

#define DD(a) std::cout << #a \" = [ \" << a << \" ]\" << std::endl;std::cout.f         


        

Answer 1

You can't get a variable (well, object)'s name in python. But you can pass the object's name to get its value (kinda the opposite of what you do with that macro)

>>> a=4
>>> locals()['a']
4

EDIT: a detailed explanation may be found here