assign output of print to a variable in python

Question

i want to know how to assign the output of print to a variable.

so if

mystring = \"a=\\\'12\\\'\"

then

print mys         


        

Answer 1

I wouldn't do it that way, personally. A far less hackish solution is to build a dictionary from your data first, and then pass it whole to a function as **kwargs. For example (this isn't the most elegant way to do it, but it is illustrative):

import re

remove_non_digits = re.compile(r'[^\d.]+')

inputList = ["a='0.015in' lPrime='0.292' offX='45um' offY='75um' sPrime='0.393' twistLength='0'",
 "a='0.015in' lPrime='0.292' offX='60um' offY='75um' sPrime='0.393' twistLength='0'",
 "a='0.015in' lPrime='0.292' offX='75um' offY='75um' sPrime='0.393' twistLength='0'", '']

#remove empty strings
flag = True
while flag:
    try:
        inputList.remove('')
    except ValueError:
        flag=False

outputList = []

for varString in inputList:
    varStringList = varString.split()
    varDict = {}
    for aVar in varStringList:
        varList = aVar.split('=')
        varDict[varList[0]] = varList[1]
    outputList.append(varDict)

for aDict in outputList:
    for aKey in aDict:
        aDict[aKey] = float(remove_non_digits.sub('', aDict[aKey]))

print outputList

This prints:

[{'a': 0.014999999999999999, 'offY': 75.0, 'offX': 45.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}, {'a': 0.014999999999999999, 'offY': 75.0, 'offX': 60.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}, {'a': 0.014999999999999999, 'offY': 75.0, 'offX': 75.0, 'twistLength': 0.0, 'lPrime': 0.29199999999999998, 'sPrime': 0.39300000000000002}]

Which appears to be exactly what you want.