Captured URL parameters in form

Question

I am using Userena and I am trying to capture URL parameters and get them to my form but I\'m lost how to do this.

What I would like to do in my template is:

Answer 1

If you use class based views, you can overwrite the def get_form_kwargs() method of the FormMixin class. Here you can pass any parameters you need to your form class.

in urls.py:

url(r'^create/something/(?P.*)/$', MyCreateView.as_view(), name='my_create_view'),

in views.py:

class MyCreateView(CreateView):
    form_class = MyForm
    model = MyModel

    def get_form_kwargs(self):
        kwargs = super( MyCreateView, self).get_form_kwargs()
        # update the kwargs for the form init method with yours
        kwargs.update(self.kwargs)  # self.kwargs contains all url conf params
        return kwargs

in forms.py:

class MyForm(forms.ModelForm):

    def __init__(self, foo=None, *args, **kwargs)
        # we explicit define the foo keyword argument, cause otherwise kwargs will 
        # contain it and passes it on to the super class, who fails cause it's not
        # aware of a foo keyword argument.
        super(MyForm, self).__init__(*args, **kwargs)
        print foo  # prints the value of the foo url conf param

hope this helps :-)