I am writing a program on a Linux system using Lazarus IDE. The program is supposed to connect to the Internet or Intranet. So, I want to display to the user list of all the
You can use ifconfig to list all available network interfaces and their status.
Edit: For doing it programmatically you have to use function ioctl with SIOCGIFCONF.
#include
#include
#include
#include
#include
#include
#include
#include
#include
int main()
{
int sockfd, len, lastlen;
char *ptr, *buf;
struct ifconf ifc;
struct ifreq *ifr;
char ifname[IFNAMSIZ + 1];
char str[INET6_ADDRSTRLEN];
sockfd = socket(AF_INET, SOCK_DGRAM, 0);
lastlen = 0;
len = 100 * sizeof(struct ifreq); /* initial buffer size guess */
for ( ; ; )
{
buf = malloc(len);
ifc.ifc_len = len;
ifc.ifc_buf = buf;
if (ioctl(sockfd, SIOCGIFCONF, &ifc) < 0)
{
if (errno != EINVAL || lastlen != 0)
exit(-1);
}
else
{
if (ifc.ifc_len == lastlen)
break; /* success, len has not changed */
lastlen = ifc.ifc_len;
}
len += 10 * sizeof(struct ifreq); /* increment */
free(buf);
}
printf("LEN: %d\n", ifc.ifc_len);
for (ptr = buf; ptr < buf + ifc.ifc_len; )
{
ifr = (struct ifreq *) ptr;
ptr += sizeof(struct ifreq); /* for next one in buffer */
memcpy(ifname, ifr->ifr_name, IFNAMSIZ);
printf("Interface name: %s\n", ifname);
const char *res;
switch (ifr->ifr_addr.sa_family)
{
case AF_INET6:
res = inet_ntop(ifr->ifr_addr.sa_family, &(((struct sockaddr_in6 *)&ifr->ifr_addr)->sin6_addr), str, INET6_ADDRSTRLEN);
break;
case AF_INET:
res = inet_ntop(ifr->ifr_addr.sa_family, &(((struct sockaddr_in *)&ifr->ifr_addr)->sin_addr), str, INET_ADDRSTRLEN);
break;
default:
printf("OTHER\n");
str[0] = 0;
res = 0;
}
if (res != 0)
{
printf("IP Address: %s\n", str);
}
else
{
printf("ERROR\n");
}
}
return 0;
}
ioctl SIOCGIFCONF will return, if success, a struct ifconf which has a pointer to an array of struct ifreq. These structs are defined in net/if.h
Using this code, from ifc.ifc_req you can get all interfaces, please look at the declaration of struct ifreq in order to determine the length and type of each array element. I think from here you can continue alone, if not please let me know.