Sort nil to the end of an array of optional strings

Question

If I have an array of optional strings, and I want to sort it in ascending order with nils at the beginning, I can do it easily in a single line:

[\"b\", nil         


        

Answer 1

Your example with Int gives a clue. If we had a max string value, we could plug that in.

This works for strings that contain only alphabetic characters:

let maxString = "~"
["b", nil, "a"].sorted{ $0 ?? maxString < $1 ?? maxString }

Or simply:

["b", nil, "a"].sorted{ $0 ?? "~" < $1 ?? "~" }